Lab 4 Solution

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Introduction: Up to now we’ve been working with single value variables. So one variable only represents one number or one character or one boolean value. But sometimes we will want to represent collections of values. For instance, we might want to store the grades of 20 students rather than just one student. Instead of declaring…

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Introduction:

Up to now we’ve been working with single value variables. So one variable only represents one number or one character or one boolean value. But sometimes we will want to represent collections of values. For instance, we might want to store the grades of 20 students rather than just one student. Instead of declaring twenty different integer variables, we can use one integer array.

An array is like a matrix in algebra. It is many different, related values which are all represented as being part of the same collection. All of these values will be stored in a continuous block of memory. In C++, arrays are always of a fixed size and you must tell the compiler what that size is when you declare the array. This can be done in two fashions:

#include <iostream>

using namespace std;

int main() {

4- Copy the following code to create, load, and print a simple array

int grades[3];

for(int i = 0; i < 3; i++){

cout << “Enter a grade for student ” << i << “: “; cin >> grades[i];

}

for(int i = 0; i < 3; i++){

cout << “Student ” << i << ” earned a ” << grades[i] << endl;

}

Notice that the first student is Student 0 because the first index in grades is 0and the last student is Student 2 because the last index in grades is 2.

5-Rewrite the body of the second for loop in problem 4 so that it shows the student’s letter grade rather than their number grade. So it should print “Student 0 earned an A” ifthat students score is between 90 and 100, B if their score is between 80 and 89, C if their score is between 75 and 79, D if their score is between 70 and 74, or else an F.

6- Your client is a property manager that oversees 8 different apartment complexes. Each complex was recently inspected and given a score of “F” for failing, “P” for passing, or “E” for excellent. The scores assigned to the complexes were: ‘E’, ‘P’, ‘F’, ‘F’, ‘E’, ‘P’, ‘E’, ‘F’. They need you to:

  1. Store the property scores in an array of the correct data type.

  1. Define a constant value to store the size of your score array.

  1. Write a loop which will count the number of excellent properties and print the result.

  1. Write a loop which will print the index of every failing property.

  1. Update the third property from failing to passing and the seventh property from excellent to passing.

7-Copy the following poorly written code. Debug it so that each line performs the action described in the comment:

//declare an array of prime numbers

int primes = {2, 3, 5, 7, 11, 13, 17}

//declare an integer named index

int index;

//declare a float named average

flot average;

//loop while index is less than 7

while index <= 7{

//add the value in primes at index to average

average = average + primes;

//update index

index+;

}

//print range of averages

cout << “Smallest prime: ” << primes[1] << ” Biggest prime: ” << primes[7] << endl;

//divide average by the count of values in primes average/7;

//print the average of the 7 numbers in primes

cout << “Average of 7 prime numbers: ” << average >> endl;

8-Build and Run your code. Fix any errors. Your output should look something like this:

9-Submit your .cpp file through TRACS as an attachment.